Помогите решить уравнение 8/3*(((3.72-0.02x)*10/37):5/6+2.8)-7/15=0,2

[latex]\frac{8}{3} *(((3.72-0.02x)* \frac{10}{37}): \frac{5}{6}+2.8)- \frac{7}{15} =0.2 \\ \frac{8}{3} *(\frac{45-0.24x}{37}+2.8)- \frac{7}{15} =0.2 \\ \frac{45-0.24x}{37}* \frac{8}{3} +2.8* \frac{8}{3} - \frac{7}{15} =0.2 \\ \frac{120-0.64x}{37} + \frac{112}{15} - \frac{7}{15} =0.2 \\ \frac{120-0.64x}{37} + \frac{112}{15} - \frac{7}{15} =0.2 \\ \frac{120-0.64x}{37} + 7 =0.2 \\ \frac{120-0.64x}{37} =-6.8 \\ 120-0.64x =-251.6 \\ 120-0.64x =-251.6 \\ 0.64x=371.6 \\ x=371.6/0.64 \\ x=580.625 [/latex]