Помогите с уравнением .9х²-4х=28

[latex]9 x^{2} -4x-28=0 \\ x_{1,2}= \frac{4б \sqrt{16+1008} }{18} = \frac{4б32}{18} = \frac{2б16}{9} \\ x_1=2,x_2=- \frac{14}{9} [/latex]

9х^2 - 4х = 28 9х^2 - 4х - 28 = 0 D = 16 + 1008 = 1024 = 32^2 X1 = ( 4 + 32 ) : 18 = 2 X2 = ( 4 -'32 ) : 18 = - 28/18 = - 14/9 = - 1 ( 5/9 )