Прошу решите !!!!!! Очень важно и срочно

[latex] \frac{(4b+5)^2+32b^2-50+(4b-5)^2}{(4b-5)^2+(4b+5)^2+50-32b^2} = \frac{16b^2+40b+25+32b^2-50+16b^2-40b+25}{16b^2-40b+25+16b^2+40b+25+50-32b^2}= \\ = \frac{64b^2}{100}=\frac{16b^2}{25}[/latex]