Рєбяткі срочно нада помощь,)))))

[latex] 1)\frac{x}{x+8}+\frac{x+8}{x-8} =\frac{x^2+x+72}{x^2-64}\\ \frac{x(x-8)+(x+8)^2}{(x+8)(x-8)} =\frac{x^2+x+72}{x^2-64}\\ \frac{x^2-8x+x^2+16x+64}{x^2-64} =\frac{x^2+x+72}{x^2-64}\\ \frac{x^2-8x+x^2+16x+64}{x^2-64} -\frac{x^2+x+72}{x^2-64}=0\\ \frac{x^2-8x+x^2+16x+64-x^2-x-72}{x^2-64} =0\\ \frac{x^2+7x-8}{(x-8)(x+8)}=0\\ x^2+7x-8=0\\ D=49+32=81=9^2\\ x_1=\frac{-7+9}{2}=1\\ x_2=\frac{-7-9}{2}=-8\\ \frac{(x-1)(x+8)}{(x-8)(x+8)}=0\\ \frac{x-1}{x-8}=0 [/latex] [latex]2) 5a^{-5}*b(4a^2b)^{-1}=5\frac1{a^5}*b*\frac1{4a^2b}=\frac5{a^5}*\frac{b}{4a^2b}=\\=\frac{5}{4a^7}[/latex] [latex] \frac{P_1}{P} =\frac{V_1}{V}\\ P_1*V=V_1*P\\ V_1=\frac{P_1*V}{P}\\ P=\frac{P_1*V}{V_1}[/latex]