Решите: Интеграл(sin^4x+cos^4x)dx

[latex]\int{(sin^4 x+cos^4 x)}\, dx=\\\\ \int{((sin^2 x+cos^2 x)^2-2sin^2x cos^2 x)}\, dx=\\\\ \int{(1-\frac {sin^2 (2x)}{2})}\, dx=\\\\ \int{(1-\frac {\frac{1-cos (4x)}{2}}{2})}\, dx=\\\\ \int{(1-\frac {1-cos (4x)}{4})}\, dx=\\\\ \int{(\frac{3}{4}+\frac {cos (4x)}{4})}\, dx=\\\\ \frac{3}{4}x+\frac{1}{16}sin(4x)+C[/latex]   c є R