Решите логарифм [latex]a) log_{3} 63 - log_{3} 9 + 0.5log_{3} \frac {27}{49} [/latex] [latex]b) log_{2} 27 - 2log_{2} 3 + log_{2} \frac {2}{3} [/latex]

a) [latex]log_3(63)-log_3(9)+0.5*log_3(27/49) =[/latex] [latex]log_3(63)-2+0.5*(log_3(27) - log_3(49))=[/latex] [latex]log_3(63) -2 + 0.5*3 - 0.5*log_3(49)=[/latex] [latex]log_3(63) -2 + 0.5*3 - log_3(49^{1/2} )=[/latex] [latex]log_3(63) -2 + 0.5*3 -log_3(7)=[/latex] [latex]log_3(63/7) -2 + 0.5*3 =[/latex] [latex]log_3(9)-2+1.5=[/latex] [latex]2-2+1.5 = 1.5[/latex] b) [latex]log_2(27)-2log_2(3)+log_2(2/3)=[/latex] [latex]log_2(27)-log_2(3^2)+log_2(2)-log_2(3)=[/latex] [latex]log_2(27)-log_2(3^2)-log_2(3)+1=[/latex] [latex]log_2(3^3)-( log_2(3^2) + log_2 (3) ) +1 =[/latex] [latex]log_2 (3^3) - log_2(3^2*3^1)+1=[/latex] [latex]log_2( \frac{3^3}{3^3} )+1 = 0+1=1[/latex]

[latex] log_{3} 63- log_{3} 9+ log_{3} \sqrt{ \frac{27}{49}}= log_{3} ( \frac{63}{9} * \frac{3 \sqrt{3} }{7} )= log_{3}3^{ \frac{3}{2} } } =1.5[/latex] [latex] log_{2} 27-log_{2} 9+ log_{2} \frac{2}{3} =log_{2} ( \frac{27}{9} * \frac{2}{3} )= log_{2} 2=1[/latex]