Решите неравенство. Срочно [latex] \frac{2x-3}{x+1} \ \textgreater \ 1[/latex]

[latex] \frac{2x-3}{x+1} \ \textgreater \ 1, \frac{2x-3}{x+1}-1\ \textgreater \ 0 [/latex] [latex] \frac{2x-3-(x+1)}{x+1}\ \textgreater \ 0 , \frac{x-4}{x+1} \ \textgreater \ 0[/latex] метод интервалов: [latex] \left \{ {{x-4=0} \atop {x+1 \neq 0}} \right. , \left \{ {{x=4} \atop {x \neq -1}} \right. [/latex]       +                     -               + -------------(-1)-----------(4)-------------->x x∈(-∞;-1)∪(4;∞)