Решите уравнение: 64-(x+3)²=0

64 - (x+3)²=0 64 - (x² + 2 * 3 * x + 9) = 0  - x² - 6x + 55 = 0 | / (-1) x² + 6x - 55 = 0 D = b² - 4ac D = 36 + 220 = 256 = 16² x₁ = [latex] \frac{-6+16}{2} [/latex] = 5 x₂ = [latex] \frac{-6-16}{2}[/latex] = -11 Ответ: x₁ = 5; x₂ = -11