Решите уравнение х(х+1)(х+5)(х+6)=50

X( x + 1)(x+ 5)( x+ 6) = 50 x(x^2 + 6x + 5)(x + 6) = 50 x(x^3 + 6x^2 + 6x^2 + 36x + 5x + 30) = 50 x( x^3 + 12x^2 + 41x + 30)= 50 x^4 + 12x^3 + 41x^2 + 30x - 50 = 0 ( x^2 + 6x - 5)(x^2 + 6x + 10) = 0 x^2 + 6x - 5 = 0 D = b^2 - 4ac = 36 + 20 = 56 x1 = ( - 6 + √56) / 2 x2 = ( - 6 - √56) /2 x^2 + 6x + 10 = 0 D = b^2 - 4ac = 36 - 40 = - 4 - дискриминант отрицательный,значит,корней нет.