Решите уравнение: log5 (4x+1)=3 log0,56(1/12x-1)=log0,56 3 lg(1-0,05x)=-1

1)log5 (4x+1) = log5 125 4x+1=125 4x=124 x=31 2)(1/12)*x-1=3 (1/12)*x=4 x=48 3)log10 (1-0.05x)=log10 0.1 1-0.05x=0.1 0.05x=0.9 x=0.9/0.05=18