Решите уравнение x(x^2 + 2x + 1) = 6(x+1)

x (x^2 + 2x + 1) - 6(x + 1) = 0  x (x + 1)^2 - 6(x + 1) = 0  (x + 1) (x (x + 1) - 6) = 0  (x + 1) (x^2 + x - 6) = 0  1) x + 1 = 0  x = - 1; 2) x^2 + x - 6 = 0  D = 1 + 4*6 = 25  x1 = ( - 1 +5)/2 = 2; x2 = ( - 1 - 5)/2 = - 3; Ответ - 3; - 1; 2