Решите уравнение:(2у-3)(3у+1)+2(у-5)(у+5)=2(1-2у)²+6у

6y^2+2y-9y-3+2(y^2-25) = 2(1-4y+4y^2)+6y6y^2-7y-3+2y^2-50 -2+8y-8y^2-6y = 0-5y-55=0-5y=55y=55:(-5)y=-11Ответ: -11

[latex](2y-3)(3y+1)+2(y-5)(y+5)=6y^{2}-9y+2y-3+2y^{2} -50=[/latex] [latex]=8y^{2}-7y-53[/latex] [latex]2(1-2y)^{2} +6y=2-8y+8y^{2} +6y=8y^{2}-2y+2[/latex] [latex]8y^{2}-7y-53=8y^{2}-2y+2[/latex] [latex]-7y-53=-2y+2[/latex] -5y=55 y=-11