Ответ(ы) на вопрос:
sin⁴(23π/12)-cos⁴(23π/12)=(sin²(23π/12)+cos²(23π/12))*(sin²(23π/12)-cos²(23π/12))=1*(sin²(23π/12)-cos²(23π/12))=-(cos²(23π/12)-sin²(23π/12))=-cos(2*(23π/12))=-cos(23π/6)=-cos(24π/6-π/6)=-cos(4π-π/6)=-cos(π/6)=-1/2
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