Нужно рассчитать массовую долю элементов: 1.H2SO4 2.HNO3 3.H2CO3 4.KMnO4 5.K2C2O7

1)M(h2so4) = 98 г/моль w(h)=(2/98)*100=2.04% w(s)=(32/98)*100=32.65% w(o)=(64/98)*100=65.31% 2)M(HNO3)=63 г/моль w(h)=(1/63)*100=1.59% w(n)=(14/63)*100=22.22% w(o)=(48/63)*100=76.2% 3)M(H2CO3)=62 г/моль w(h)=(2/62)*100=3.23% w(c)=(12/62)*100=19.05% w(o)=(48/62)*100=77.42% 4)M(KMnO4)=158 г/моль w(K)=(39/158)*100=24.96% w(Mn)=(55/158)*100=34.81% w(o)=(64/158)*100=40.51% 5)M(K2C2O7)=214 г/моль w(K)=(78/214)*100=36.45% w(c)=(24/214)*100=11.215% w(o)=(112/214)*100=52.34%