Решите неравенство (2-x)^2 меньше 5

[latex] (2-x)^2\ \textless \ 5, \\ 4-4x+x^2-5\ \textless \ 0, \\ x^2-4x-1\ \textless \ 0, \\ x^2-4x-1=0, \\ D_{/4}=5, x_1=2-\sqrt5, x_2=2+\sqrt5, \\ a=1\ \textgreater \ 0, \\ x\in(2-\sqrt5;2+\sqrt5).[/latex]