Сократите дроби а²-3/а+√3 5-√5/√5 √в-√с/в-с

[latex] \frac{a^2-3}{a+ \sqrt{3} } = \frac{(a- \sqrt{3})(a+ \sqrt{3} ) }{a+ \sqrt{3} } = a- \sqrt{3} \\ \\ \frac{5- \sqrt{5} }{ \sqrt{5} } = \frac{ \sqrt{5} ( \sqrt{5}-1) }{ \sqrt{5} } = \sqrt{5} -1 \\ \\ \frac{ \sqrt{b} - \sqrt{c} }{b-c} = \frac{ \sqrt{b} - \sqrt{c} }{(\sqrt{b} - \sqrt{c}) (\sqrt{b} + \sqrt{c}) }= \frac{1}{\sqrt{b} + \sqrt{c}} [/latex]

1. (а²-3)/(а+√3) = ((a-√3)(a+√3))/(a+√3) = a-√3; 2. (5-√5)/√5 = (√5(5-√5))/5 = (5√5-5)/5 = 5(√5-1)/5 = √5-1; 3. (√b-√c)/(b-c) = (√b-√c)/((√b-√c)(√b+√c)) = 1/(√b+√c)