Вычеслите log1,2[25/36*(6/5) наверху 3,2] помогите срочно прошу((((

[latex]log_{1,2}[\, \frac{25}{36}\cdot (\frac{6}{5})^{3,2}\, ]=log_{\frac{6}{5}}[\, (\frac{5}{6})^2\cdot (\frac{6}{5})^{\frac{16}{5}}\, ]=log_{\frac{6}{5}}[\, (\frac{6}{5})^{-2+\frac{16}{5}}\, ]=\\\\=log_{\frac{6}{5}}[\, (\frac{6}{5})^{\frac{6}{5}}\, ]=\frac{6}{5}\cdot log_{\frac{6}{5}}\frac{6}{5}=\frac{6}{5}\cdot 1=\frac{6}{5}[/latex]

∫₁²(3x-3/x)dx=3x²/2-3*lnx I₁²=3*2²/2-3*ln2-3*1²/2+ln1= =6-ln8-1,5+0=1-1,5=4,5-ln8≈2,42.