Контрольная работа: Основная задача механики
=0,825t
at m =R3 =40*0,825t=33t
an m =R3 2 3 =40*(0,825t)2 =40*(0,825(t)2
a=
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Дано :R2 =15; r2 =10; R3 =15; r3 =15
X=C2 t2 +C1 t+C0
При t=0 x0 =6 =3
t2 =2 x2 =80 см
X0 =2C2 t+C1
C0 =10
C1 =7
80=C2 *22 +3*2+6
4C2 =80-6-6=68
C2 =17
X=17t2 +3t+6
=V=34t+3
a==34
V=r2 2
R2 2 =R3 3
3 =V*R2 /(r2 *R3) =(34t+3)*15/10*15=3,4t+0,3
3 =3 =3,4
Vm =r3 *3 =15*(3,4t+0,3)=51t+4,5
at m =r3
=3,4t
at m =R3 =15*3,4t=51t
an m =R3 2 3 =15*(3,4t+0,3)2 =15*(3,4(t+0,08)2
a=
Решение второй задачи механики